Nifty EOD 10-01-2012

Updating the Count-chart from yesterday:


For academic purposes,how should the a b c of this Z be labelled.Posting three alternatives:





Anyways,whichever way we label it,tentatively
Z.a=4588-4780=192
Z.b=4780-4687=93
Z.c=Z.a=192 should ideally reach 4687+192=4879 or do a maximum 4994(where Z.c=1.6*Z.a).
An attempt has been made to do internal five sub-waves of Z.c in the Chart above,
wherein an ideal 5 wave Z.c would take following form:
(i)=4687-4795=108
(ii)=4795-4696=99
(iii)=min 1.62*(i)=175=4871
(iv)=min 23.4% of (iii)=41=4830
(v)=(i)=4938
Thus we should be ready for 4900+ levels tomorrow

Raghu